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Calc II Midterm 3

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nth Term Test for Divergence
if lim an # 0, then 8Mk=1 an diverges
Harmonic Series
8Mk=1 1/k = 1+1/2+1/3+1/4+..., which diverges
8Mk=0 a0rk
a/(1-r) if |r|<1
nth degree Taylor Polynomial of f(x) at x = a
Pn(x) = nMk=0 f(k)(a) * 1/k! * (x-a)k
Remainder of nth degree Taylor Polynomial
Rn(x) = fn+1(z)/(n+1)! * (x-a)n+1
Estimate f(x)
f(x) = Pn(x) + Rn(x) for some z betseen x and a
ranking of n powers
ln(n) (lt) n, n^2, n^3 (lt) 2^n, 3^n, 4^n (lt) n!, n^n
p-series
8Mn=1 1/np converges if p>1
Integral Test
8Mn=1 an, 1~8 f(x)dx = lim(t->8) 1~t f(x)dx, if 8Mn=1 an is a positive-term series and f is a continous positive-valued, decreasing (eventually) function for eacn n = 1, 2, 3, etc.
Comparison Test - convergence
M an and M bn are positive-term series, if Mbn converges and an(lt)bn for every n, then an converges
Comparison Test - divergence
M an and M bn are positive-term series, if bn diverges and an > bn for every n, then an diverges
Comparison Test examples
p/(q+k) < p/q < (p+k)/q, try to simplify to geometric or p-series
Limit Comparison Test
Suppose An and Bn are positive-term series; 1)If lim An/Bn = L with 0(lt)L(lt)8, then either both converge or both diverge 2)if lim An\\Bn = 0 and Bn converges, An converges 3) If lim An\\Bn = 8 and Bn diverges, then An diverges
Alternating Series Test for Convergence
Suppose 8Mn=1 (-1)^(n+1)an is an alternating series. If 1)0(lt)a[n+1](lt)a[n] for every n, and lim a[n] = 0, then (-1)^(n+1)converges
Definition of Conditionally Convergent
MAn converges but M|An| diverges (only on Alternating Series and by Limit Comparison or Integral and Alternating Series Test)
Definition of Absolutely Convergent
both MAn and M|An| converges
Ratio Test
p = lim|An+1/An| Then An converges if p<1, An diverges if p>1, and test is inconclusive if p=1
Root Test
p = lim |An|1\\n Then An converges if p(lt)1, An diverges if p>1, and test is inconclusive if p=1
Power Series
8Mn=0 anxn = A0+A1x+A2x2+...
Unit Vector
v is vector. u = v/|v| = v1/|v|, v2/|v|
Dot Product of v and u
u1v1+u2v2+...
Test for v and u being parallel
u = cv for real number c
Test for v and u being perpendicular
u.v = 0
Angle between u and v
u.v = |u||v| cos(())
Vector Cross Product
uxv= |i j k| |u1 u2 u3| |v1 v2 v3|
Area through vectors
A = 1\\2|u||v|sin(()) = 1\\2|uxv|
Volume of vectors
V = |a.(bxc)|
Row Equivalent Operations
1)Switch two rows; 2)Multiply any row by constant; 3)Add a row to another
Decreasing function
if f\'(x) < 0 OR bottom increases while top doesn\'t

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